You are running a bingo game where you want to tweet the winner of each round of the game. You want to announce the name of who won, and how much they won in dollars. Make a function that takes those two words in as input, and then announces the win. For now, just print the statement that you will want to tweet later. (Hint: Remember that you are taking a number as input, which has to be converted to a string to concatenate it.)

In outlook how can cherie look at the details of an event that appears on the month view of her calendar? check all that apply. by switching to the detail view by switching to the week view by switching to the day view by right-clicking on the event by double-clicking on the event by highlighting the event

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Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput. find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }