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Write a C++ expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".

#include
#include
using namespace std;

int main() {
double targetValue = 0.3333;
double sensorReading = 0.0;

sensorReading = 1.0/3.0;

if (/* Your solution goes here */) {
cout << "Equal" << endl;
}
else {
cout << "Not equal" << endl;
}

return 0;
}

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Answers: 1

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Write a C++ expression that will cause the following code to print "Equal" if the value of sensorRea...

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