For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle class is given below. (For this assignment, you will have to submit 2 .java files: one for Rectangle class and the other one for RectangleClient class.) // A Rectangle stores an (x, y) coordinate of its top/left corner, its width and height. public class Rectangle { private int x; private int y; private int width; private int height; // constructs a new Rectangle with the given inX, inY and inSideLength public Rectangle(int inX, int inY, int inWidth, int inHeight) // returns the fields' values public int getX() public int getY() public int getWidth() public int getHeight() public int getArea() public bool IsSquare() // returns a string such as "Rectangle located at (1,2) with dimensions 3x4 and area 49.", where 3 is width, 4 is height and 12 is the area. public String toString() ... }

Java.

Explanation:

public class Rectangle {

   private int x;

   private int y;

   private int width;

   private int height;

   public Rectangle(int inX, inY, inWidth, inHeight) {

       x = inX;

       y = inY;

       width = inWidth;

       height = inHeight;

   }

   public int getX() {

       return x;

   }

   public int getY() {

       return y;

   }

   public int getWidth() {

       return width;

   }

   public int getHeight() {

       return height;

   }

   public int getArea() {

       return width * height;

   }

   public bool isSquare() {

       if (width == height) {

           return true;

       }

       else

           return false;

   }

   public String toString() {

       return "Rectangle located at (" + x + "," + y + ")" + "with dimensions " + width + "x" + height + "and " + getArea() + "is the area.";

   }

}

i would say 3 because windows is the best but vista doesnt do updates anymore

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