A ball is released from a 10 m high roof and bounces two thirds as high on each successive bounce. After traveling a total of 40 m (up and down motion), how many times did the ball bounce (e. g. touch the ground)? Put the answer in

Four times traveling 40,12345 mts

Explanation:

We can express this as a sum as follows

The first term is the dropping part and the second is the upward motion. this sums up to 40,12345 m after bouncing four times. As a program we could write using the while loop.

distance=0;

i:=0;

while distance<40 do

i:=i+1;

distance:=distance+

end while;

Here the answer is in i and the closest distance traveled after reaching 40 is in the variable distance.

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explanation:

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