For this lab, youhave to write a .cthat prompts user to enter two values, x and n. Then it would use a function to compute the sum of the series. It will take two arguments, x and n. It will return the sum of the series.

The question is incomplete! Here is the complete question and it’s answer!

Question:

For this lab, you have to write a programnamedseriesFunction.cthat prompts user to enter two values, x and n. Then it would use a function to compute the sum of the series. It will take two arguments, x and n. It will return the sum of the series.

S(x) = x + (x+1) + (x+2) + (x+3) + (x+4) +........................+(x + n - 1) + (x + n)

As an example, for input values x = 100 and n = 0, it should output 100. For x = 100 and n = 1, it should output 100 + 101 = 201.

Step by Step Explanation:

We are required to find the sum of the following series.

S(x) = x + (x+1) + (x+2) + (x+3) + (x+4) +........................+(x + n - 1) + (x + n)

We have created a function seriesFunction which takes two inputs x and n and calculates the sum of the series (x+n). A for loop is used to run n times and a sum variable is used to keep adding n number of times.

Then we have driver code in the main function where we ask the user to enter x and n values and then called the seriesFunction to calculate the sum of series

Code:

#include <iostream>

using namespace std;

 int seriesFunction(int x, int n)

 {

     int sum;

     for(int i = 0; i <= n; i++)

     sum = sum + (x+i);

     cout<<"sum of series: "<<sum<<endl;

 }

int main()

{

   int x,n;

   cout << "Enter x"<<endl;

   cin >> x;

   cout << "Enter n"<<endl;

   cin >> n;

   seriesFunction(x,n);

   return 0;

}

Output:

Test 1:

Enter x

100

Enter n

1

sum of series: 201

Test 2:

Enter x

100

Enter n

4

sum of series: 510

answerlibraries;

answeruse the nslookup utility;