2.29 lab: using math functions given three floating-point numbers x, y, and z, output x to the power of z, x to the power of (y to the power of 2), the absolute value of y, and the square root of (xy to the power of z). output each floating-point value with two digits after the decimal point, which can be achieved as follows: printf("%0.2of", your value); ex: if the input is: 5.0 6.5 3.2 the output is: 172.47 340002948455826440449068892160.00 6.50 262.43

The solution code is written in C++

Explanation:

Firstly, let's declare three variables x, y and z with double type (Line 1).

We prompt user for three floating point values and assign each of the input to x, y, z, respectively (Line 4).

Next, use printf() function to output the result based on the mathematical expression as required by questions. The "%0.2f" in printf() function enable us to output the floating-point value with two digits after the decimal point(Line 6-9).

The code is in C.

We use the built-in functions to make the required calculations. These functions are already defined in C. We need to import math.h to be able to use the pow(), fabs(), and sqrt() functions

Comments are used to explain each line of the code

//main.c

//importing the required libraries

#include <stdio.h>

#include <math.h>

#include <stdlib.h>

int main(){

  //Declaring the variables x, y, z

  float x, y, z;

  //Getting inputs for x, y, z

  scanf("%f", &x);

  scanf("%f", &y);

  scanf("%f", &z);

  //Calculating the x to the power of z using the pow function

  double result1 = pow(x, z);

  //Calculating the x to the power of (y to the power of 2) using the pow function inside the another pow function

  double result2 = pow(x, pow(y, 2));

  //Calculating the absolute value of y using the fabs function

  double result3 = fabs(y);

  //Calculating the square root of (xy to the power of z) using the sqrt and pow functions

  double result4 = sqrt(pow(x * y, z));

  //Printing the results using prinntf("%0.2f") to get the two digits after decimal value

  printf("%0.2f\n", result1);

  printf("%0.2f\n", result2);

  printf("%0.2f\n", result3);

  printf("%0.2f\n", result4);

  return 0;

}

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