The square of n can be calculated by noting that square(n) = square(n-1) + diff(n-1). diff(n) = diff(n-1)+2. the square(0)=0, diff(0)=1. what is the stopping condition for this recursive definition? a. unknown b. n=1 c. n=-1 d. n=o

d. n=0

Explanation:

The recursive definition stops when the variables square and diff are attributed fixed values.

It happens at n = 0, as square(0) = 0, diff(0) = 1.

So the correct answer is:

d. n=0

it could be e. idk for sure

you are welcome for my answer it is b⇔⇒⊕