Nents delivery/ua/mt/launch/48955169/4526 5726/ahrochm6ly9mmsshchauzwrizw50dw ouy29tl2x/yxjuzxivc2vjuzskinulundu< br />ube
maps
ating documents: mastery test
select the correct answer.
annie is a nutritionist. she is conducting seminars about following a healthy diet in various offices. annie adds a picture of fruit in a document
she wants to enhance it to give a cut-out look. which feature or menu option should she use?
a
smartart
b.
clip art
oc charts
d.
shapes
reset
next

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }