Suppose you have a risc machine with a 2.8 ghz clock (i. e., the clock ticks 2.8 billion times per second). this particular computer uses an instruction cache, a data cache, an operand fetch unit, and an operand store unit. the instruction set includes simple instructions with the following timings: set reg, immed 2 clock cycle loop label 6 clock cycles add reg, immed 2 clock cycle add reg, reg 3 clock cycles load reg, mem 4 clock cycles assume that the following code fragment is used to sum the element of a numeric array. if the initialization code has already executed (i. e. the set instructions have already finished execution) how many array elements can be processed in 3.2 ms? round your answer to the nearest integer. recall that 1 ms = 0.001 seconds. also assume that there are no physical memory limitations, implying that the array can be as large as desired. set r1, 0 ; initialize sum set r2, max_size ; initialize loop counter set r3, @list ; initialize array pointer more: load r4, \textrm{3.0} ; fetch current list element add r1, r4 ; add current list element add r3, 4 ; move array pointer to next element loop more ; auto-decrement r2, jump to more if r2 ! = 0