C++ consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". any value that is the same as the immediately preceding value is considered a consecutive duplicate. in this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. note that the last 3 is not a consecutive duplicate because it was preceded by a 7. write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. when the code exits the loop it should print the number of consecutive duplicates encountered. in the above case, that value would be 3.

Ap practice - performance task response the ap create performance task asks you to write about an abstraction that you developed and wrote into your code. most of the time that means identifying a function or procedure you wrote to "manage complexity" in your program. here is the actual prompt from the create performance task: 2d. capture and paste a program code segment that contains an abstraction you developed individually on your own (marked with a rectangle). this abstraction must integrate mathematical and logical concepts. explain how your abstraction manage the complexity of your program. (must not exceed 200 words) below is a segment of code from an "under the sea" program with a rectangle drawn around a portion of the code identifying an abstraction. imagine that you wrote this and are composing an ap response about how this abstraction manages complexity. (note: ignore the requirement that the abstraction integrate "mathematical and logical concepts" for this practice response. just write about managing complexity). explain how the abstraction marked with the rectangle in the code above manage complexity of this program. write your response here submit

If your accelerator suddenly gets stuck what should you do

Write a method so that the main() code below can be replaced by the simpler code that calls method original main(): public class calcmiles { public static void main(string [] args) { double milesperhour; double minutestraveled; double hourstraveled; double milestraveled; milesprhour = scnr. nextdouble(); minutestraveled = scnr. nextdouble(); hourstraveled = minutestraveled / 60.0; milestraveled = hourstraveled * milesperhour; system. out. println("miles: " + milestraveled); } }