Computers and Technology, 13.09.2019 17:10 6mario5

For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we increase voltage by 20 percent and increase clock rate by 20 percent?
i do not want you to answer the question for me, but give me the step to solve this. how do i solve this problem.

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Iknow this one is you press the tab key.

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something will pop up that says “know the answer? answer now! ” and you click on it and write your answer. after you are done, submit it.

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The best answer is c) the main() methodfor java, that will be the main starting/entry point. the other choices are generally irrelevant.a java program need not access a firewall, especially if it is designed to work offline. a firewall only deals with networking; it will not be relevant for all java programs.microsoft excel is not relevant for all java programs.a colon is too general.

Answer from: Quest

The answer is c. 36======analyzing the for-loop, we see that the control variable, k, starts at 0 and increments by after every loop iteration. the condition $\texttt{k\ \textless \ =7}$ tells us that the loop will stop when k is above 7; in this case, when k is 8.0 1 2 3 4 5 6 7 are the values for k that will be used. each number is for each iteration; therefore, the for-loop will have 8 iterations in total.the code inside the loop itself goes like this: 1st iteration (k=0)starting with sum=0, val=1 $\texttt{sum += val; }$ means that add $\texttt{val}$ to $\texttt{sum}$ .since sum is 0 and val is 1, 0 + 1 = 1. the new value of sum is 1. $\texttt{val++; }$ means to increment $\texttt{val}$ by 1.since val is 1, the new value of val of 2.end of iteration with k=0; k is increased by one to become k=12nd iteration (k=1)starting with sum=1, val=2 $\texttt{sum += val; } \iff \texttt{sum = 1 + 2}$ ======let us establish a pattern. this is moreso logic than programming: we can rewrite $\texttt{sum = 1 + 2}$ so that we have the elements from the previous iteration. the 1 came from 0 + 1 before. so we can write it as $\texttt{sum = 0 + 1 + 2}$ .and if we did the third iteration, by the end, sum would look like $\texttt{sum = 0 + 1 + 2 + 3}$ notice how the number of plus signs is equal to the iteration you are on (which is just k+1), and what is being added is increasing by one each time. for example, the third iteration (k=2) ends up with $\texttt{sum = 0 + 1 + 2 + 3}$ with 3 plus signs.the second iteration (k=1) ends up with $\texttt{sum = 0 + 1 + 2}$ with two plus signs.the first iteration (k=0) ends up with $\texttt{sum = 0 + 1}$ with one plus sign.this is a pattern. the nth iteration will have n plus signs.since we established before that there are 8 iterations of this loop in total, the value of sum at k=7 (the 8th and last iteration) will have sum with 8 plus signs. $\begin{aligned} \texttt{sum} & = \texttt{0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{3 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{6 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{10 + 5 + 6 + 7 + 8 } \\ & = \texttt{15 + 6 + 7 + 8 } \\ & = \texttt{21 + 7 + 8 } \\ & = \texttt{28 + 8 } \\ & = \texttt{36} \end{aligned}$ so the value of sum at the end of the loop is 36.

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For a new version of processor, suppose the capacitive load remains, how much more energy will the p...