Define a function that creates a list of all the numbers that are factors of the user's number. for example, if the function is called factor, factor(36) should return [1, 2, 3, 4, 6, 9, 12, 18, 36]. the numbers in your list should be sorted from least to greatest, and 1 and the original number should be included.
remember to consider negative numbers as well as 0.

#function that return all the factor of a number

def factor(num):

   #create an empty list

   lst=[]

   #if input is positive

   if num>0:

       for i in range(1,num+1):

           if num%i==0:

               lst.append(i)

   #if input is negative            

   elif num<=0:

       for i in range(num,0):

           if num%i==0:

               lst.append(i)

   # return the list of all factors            

   return lst

# read the number from user

x = int(input ( "Enter the number:: " ))

print("factors of the number are:")

# call the function with parameter x

print(factor(x))

print('\n')

Explanation:

Read a number from user. Call the function "factor()" with parameter "x". In the function create an empty list. if the input is positive then check all the number from 1 to input. If a  number divides the input then add it into list.If input is negative then check all the number from input to 0. if a number divides the input then add it to the list. After that return the list.

#Output:

Enter the number:: 36                                                                                                          

factors of the number are:                                                                                                    

[1, 2, 3, 4, 6, 9, 12, 18, 36]

Enter the number:: -16                                                                                                        

factors of the number are:                                                                                                    

[-16, -8, -4, -2, -1]

answer ingenuity;

answer inspecting packets in isolation from their context;