Write a method that accepts an integer argument and returns the sum of all the integers from 1 up to (and including) the number passed as an argument. for example, if 3 is passed as an argument, the method will return the sum of 1+2+3, which is 6. use recursion to calculate the sum. test your method in main by prompting the user to enter a positive integer to sum up to. provide input validation so that only positive values are accepted.

Here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// recursive function to calculate sum from 1 to n

int calculate_sum(int n)

{

if (n <= 1)

 return n;

return n + calculate_sum(n - 1);

}

// Driver code

int main()

{

   // variable to read input

int n;

cout<<"Please Enter a number: ";

//reading input from user

cin>>n;

do{

    if(n<=0)

    {

    cout<<"please enter only positive numbers(greater than 0):"<<endl;

    cin>>n;

    }

} while(n<=0);

// calling the recursive function and printing the sum

cout << "Sum of all numbers from 1 to "<<n<<" is: "<<calculate_sum(n);

return 0;

}

Explanation:

Read input from user and assign it to variable "n".if the input is less

than or equal to 0, it will again ask user to enter a number greater than 0.

then Call function calculate_sum() with argument "n". This function will

calculate sum recursively from n to 1.when recursive function call itself for

n<=1 (base condition),it calculate the total sum.

Output:

Please Enter a number: -5

please enter only positive numbers(greater than 0):

6

Sum of all numbers from 1 to 6 is: 21

for this, you need the pythagorean theorem, which is a^{2}+ b^{2}= c^{2}

your a should be 12, and your b should be 35. so now you can solve for c, which equals 37 miles.

so the answer is 37 miles

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explanation:

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