Write a function drivingcost() with input parameters drivenmiles, milespergallon, and dollarspergallon, that returns the dollar cost to drive those miles. all items are of type double. if the function is called with 50 20.0 3.1599, the function returns 7.89975. define that function in a program whose inputs are the car's miles/gallon and the gas dollars/gallon (both doubles). output the gas cost for 10 miles, 50 miles, and 400 miles, by calling your drivingcost function three times.

#include <iostream>

using namespace std;

double DrivingCost(int drivenMiles,double milesPerGallon,double dollarsPerGallon)

{

   double dollarsperMile=dollarsPerGallon/milesPerGallon;//calculating dollarsperMile.

   return dollarsperMile*drivenMiles;//returning thr driving cost..

}

int main() {

double ans;

int miles;

cout<<"Enter miles"<<endl;

cin>>miles;

ans=DrivingCost(miles,20.0,3.1599);

cout<<ans<<endl;

return 0;

}

Output:-

Enter miles

10

1.57995

Enter miles

50

7.89975

Enter miles

100

15.7995

Explanation:

In the function first I have calculated the dollars per mile and after that I have returned the product of dollarspermile and driven miles.This will give the cost of the Driving.

i don't think so. although it would be nice. i am pretty sure that was an option an update or two ago. i guess they want you to stay 14 forever. haha.

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