What will the following code display? #include using namespace std; void dosomething(int); int main() { int x{2}; cout < < x < < '\n'; dosomething(x); cout < < x < < '\n'; return 0; } void dosomething(int num) { num = 0; cout < < num < < '\n';

The code will display the following on the screen:-

2

0

2

Explanation:

The output is like this because x{2} assigns the value 2 to the integer x.First the value of x is printed on the screen that is 2 and that newline is used to go to the next line.After that function is called doSomething with x passed as the argument. doSomething function assigns the value zero to the variable passed and prints it on the screen.So the next line is 0.Since x is passed by value so no changes will appear in the original argument.Hence the last line printed is 2.

answer; monitor is the correct answer. good luck

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