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An example of hardware is a word processor database mouse e-mail

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Computers and Technology, 22.06.2019 03:30, raytaylorh010801
Write a computer program to calculate the three-phase fault current for a fault at f in figure 1.16, with the network normal, and with one line at a time removedproblems 1.1 write a computer program to calculate the three-phase fault current for a fault at f in figure 1.16, with the network normal, and with one line at a time removed 20 power system relaying from service. the positive-sequence impedance data are given in the accompanying table. use the commonly made assumption that all prefault resistance values are (1.0+j0.0) pu, and neglect all resistance values. calculate the contribution to the fault flowing through the cb b and the voltage at that bus. for each calculated case, consider the two possibilities: cb b2 closed or open. the latter is known as the stub-end fault í• figure 1.16 problem 1.1 system data for figure 1.16 from to positive sequence 0.0+j0.1 0.05j0.15 0.04 j0.2 0.01 jo. i 0.015 + j0.15 0.01 j0.19 0.01 +j0.19 0.03+j0.1 0.0+j0.08 6 6 6 from service. the positive-sequence impedance data are given in the accompanying table. use the commonly made assumption that all prefault resistance values are (1.0 + j 0.0) pu, and neglect all resistance values. calculate the contribution to the fault flowing through the cb b1, and the voltage at that bus. for each calculated case, consider the two possibilities: cb b2 closed or open. the latter is known as the “stub-end” fault.
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Computers and Technology, 22.06.2019 06:30, Nicki3729
Exchanging which type of data uses the least bandwidth? music photographs video voice bandwidth- the amount of data that can be moved between two points in a set time period
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Computers and Technology, 23.06.2019 02:30, jaueuxsn
Which component acts as a platform on which application software runs
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Computers and Technology, 24.06.2019 02:00, arubright177
Write an expression that will cause the following code to print "equal" if the value of sensorreading is "close enough" to targetvalue. otherwise, print "not equal". ex: if targetvalue is 0.3333 and sensorreading is (1.0/3.0), output is:
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