Consider 2nh3(g)+3cuo(s)→n2(g)+3cu(s)+3h2o(g ) 2nh 3 (g)+3cuo(s)→n 2 (g)+3cu(s)+3h 2 o(g). what volume (in ml) of nh3 nh 3 is required to completely react 45.2 g of cuo at stp? enter your solution as a numerical value with no units.

The volume of  in Ml  of NH3  required  to completely  react  with  45.2 g  of CUO   at  STP  is 8489.6 Ml

 calculation
calculate the moles  of CUO  used
moles= mass/molar mass
45.2 g/79.5 g/mol =0.569 moles

Reacting  equation 
2NH3  + 3CUO = N2  +3CU  +3H2O
by  use of reacting  ratio  between  NH3 to CUO  which jis  2:3 the moles of  NH3  = 0.569 x2/3 = 0.379 moles

At STP  1  mole  = 22.4 L
what about  0.379 moles

=0.379  x22.4  = 8.4896  L

in  Ml  = 8.4896  x1000 =8489.6 ml

Sorry i dont understand the question can you rephase it?

Sorry i dont understand the question can you rephase it?