Given the balanced ionic equation representing a reaction: in this reaction, electrons are transferred from a) al to mg2+ b) al3+ to mg c) mg to al3+ d) mg 2+ to al pls explain

2Al³⁺ (aq) + 3 Mg⁰ (s) --> 3Mg²⁺ (aq) + 2Al⁰ (s)

Al³⁺  +3e⁻ > Al⁰ 
Al had positive charge and them it became neutral, that means that it took 3 negative particles (electrons).    (+3-3=0)
We have 2 Al³⁺, and they take 3*2 =6 electrons

Mg⁰  > Mg²⁺ + 2e⁻
Mg was neutral atom, and them it became positive ion, that means it lost electrons .  (0=+2-2)
We have 3Mg, and they loose 2*3=6 electrons.

Mg loose electrons, Al³⁺ takes electrons, that means that electrons are transferred from  Mg to Al³⁺.

Answer is C).