How much heat is required to vaporize 43.9 g of acetone at its boiling point?

The heat required to vaporize 43.9 g  of acetone  at its boiling point is calculated as  below

 the heat of vaporization of acetone at its boiling  point is  29.1 kj/mole

find the moles of  acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole  x 0.757 moles = 22.03 kj

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.