How many grams of mgcl2 (molar mass = 95.20 g/mol) will be formed from 25.6 ml of a 0.100 m hcl solution reacting with excess magnesium metal? (the other product is hydrogen gas.)

0.1219 g

Explanation:

mole = mass/molar mass = molarity x volume

From the balanced equation of reaction:

1 mole of MgCl2 is formed from 2 moles of HCl

x mole of MgCl2 is formed from 0.1 x 0.0256 moles HCl

x mole of MgCl2 = 1 x 0.1 x 0.0256/2

                               = 0.00128

0.00128 moles of MgCl2 is formed from 0.00256 moles HCl

Hence,

mass of MgCl2 = moles x molar mass

                          = 0.00128 x 95.20

                            = 0.1219 g

Therefore, 0.1219 g of MgCl2 will be formed from 25.6 mL of a 0.100 M HCL solution reacting with excess magnesium metal.

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