If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form

Reaction of Copper with Mercuric Nitrate is as follow,

                       Cu  +  Hg(NO₃)₂    →    Cu(NO₃)₂  +  Hg

According to equation,

                            1 Mole of Cu reacts to form  =  1 Mole of Hg

So,

           1.20 Moles of Cu will react to produce  =  X Moles of Hg

Solving for X,

                                   X  =  (1.20 mol × 1 mol) ÷ 1 mol

                                   X  =  1.20 mol of Hg
Result:
          1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.

C) ideal gas law the ideal gas law. the volume (v) occupied by n moles of any gas has a pressure (p) at temperature (t) in kelvin. the relationship for these variables, p v = n r t, where r is known as the gas constant, is called the ideal gas law or equation of state.

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)