Chemistry, 22.07.2019 02:30 maddiecat43551p2rueh

If 2500. j of energy are added to 120. g of benzene at 30. degrees c, what will be its final temperature?

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When heat (q) is absorbed by "m" grams of a substance then the change in temperature is given as,

q = m Cp (T₂ - T₁) --- (1)

where;
Cp = Specific Heat

Specific heat of Benzene is 1.72 J/g.°C

Now,
Solving equation 1,

(T₂ - T₁) = q / m Cp
Putting values,
(T₂ - 30 °C) = 2500 J ÷ (120 g ×1.72 J/g.°C)

(T₂ - 30 °C) = 2500 J ÷ (206 J/°C)

(T₂ - 30 °C) = 12.13 °C

T₂ = 12.13 °C + 30 °C

T₂ = 42.13 °C

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

i need mutiple choices

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