What volume of 1.10 m srcl2 is needed to prepare 525 ml of 5.00 mm srcl2?

- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

Where, and are molarities of concentrated and diluted solutions and and are their respective volumes.

= 1.10M

= 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

= ?

= 525 mL

Let's plug in the given values in the formula:

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

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