Agas occupies 11.2 liters at 0.860 atm. what is the pressure if the volume becomes 15.0 l

Boyle shows the relationship between the pressure of gas and its volume at a constant temperature.

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is V₁ and its pressure is P₁. assuming that its volume has been increased to V₂, according to Boyle's law its pressure will decrease if the new pressure is P₂.

P₁ V₁ =P₂V₂

P₁ = 0.860 atm
V₁ = 11.2 L
P₂ = ?
V₂= 15 L 

0.860 atm x 11.2 L = P₂ x 15 L

P₂ =  0.642 atm

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :