What is the number of sulfur atoms that equal a mass of 32.07 amu?

As we know that mole of Sulfur is related to Number of Atoms and Mass as follow,

                                  1 Mole  =  6.022 × 10²³ Atoms

                                  1 Mole  =  32.07 g

It means 1 Mole of Sulfur contain 6.022 × 10²³ Atoms and weights 32.07 g.

Result:
           32.07 g of Sulfur contains 6.022 × 10²³ Atoms.

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