Calculate how many moles of nacl would be necessary to prepare 100.0 ml of 0.517 m nacl solution.

It would be necessary 0.052 moles of NaCl to prepare the solution.

Explanation:

The Molarity concentration unit represents the moles of solute that are contained in 1 L (or 1000 mL) of solution.

In this case, 0.517 M means that there are 0.517 moles of NaCl (solute) in 1 L of solution, but we need to prepare only 100 mL of solution. So, using a "Rule of three" we can find the number of moles.

The "Rule of three" reasoning is: If 1000 mL of solution has 0.517 moles of NaCl, the 100 mL that we need to prepare will contain "x" moles.

1000 mL 0.517 moles of NaCl

 100 mL x = (100 mL . 0.517 moles)/1000 mL = 0.052 moles of NaCl

- Remember that Molarity is represented by capital "M" and not by lowercase "m" because lowercase "m" represents the concentration unit of "molality" in chemistry.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.