How many grams of magnesium chloride can be produced if we react 32.50 g mg with 32.50 g hcl

The mass   of magnesium  chloride produced is  calculated as follows

write the  equation  for  reaction
Mg +2HCl=MgCl +H2
find the moles  of  each reactant
moles  =  mass/molar  mass
moles for mass =  32.5 g/24.3 g/mol= 1.34  moles
moles  for HCl =  32.5g /  95.3 g/mol=0.89 moles

HCl  is the limiting  reagent   hence  by  use of mole  ratio   between HCl  to MgCl2  which is   2:1  the moles of  MgCl2  is therefore =  0.89/2 =0.445 moles

mass of MgCl2  is therefore=  moles/molar  mass
=0.445moles  x 95.3 g/mol=  42.4 grams  of MgCl2

7is b8 is d9 is c10 is a11 is d

You would do 1500/4 and the answer is 375