For the reaction cl2 + 2kbr → 2kcl + br2, how many moles of potassium chloride are produced from 331.1 g of potassium bromide?

Equation is as follow,

                                   Cl₂  +  2 KBr    →    2 KCl  +  Br₂

According to equation,

                 238 g (2 moles) KBr produced  =  2 Moles of KCl
So,
                      331.1 g of KBr will produce  =  X moles of KCl

Solving for X,
                                 X  =  (331.1 g × 2 mol) ÷ 238 g

                                 X  =  2.78 Moles of KCl
Result:
           331.1 g of KBr produces 2.78 Moles of KCl.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na