When the reaction p4o10 + koh → k3po4 + h2o is balanced, how much koh is required to react with 3 moles of p4o10? 1. 9 mol 2. 3 mol 3. 18 mol 4. 36 mol 5. 27 mol?

The balanced equation for the above reaction is as follows;
P₄O₁₀ + 12KOH ---> 4K₃PO₄  + 6H₂O
stoichiometry of P₄O₁₀ to KOH is 1:12
1 mol of P₄O₁₀ reacts with 12 mol of KOH
therefore 3 mol of P₄O₁₀ reacts with - 12 x 3 mol of KOH
the number of KOH moles required to react with P₄O₁₀ - 36 mol of KOH
answer is 4. 36 mol