What is the molar solubility of mgf2 in a 0.42 m naf solution? for mgf2, ksp = 8.4 × 10–8?

-when Ksp is the solubility product  constant for a solid substance when it

dissolved in the solution. and measure how a solute dissolves in the solution.

- and when the solubility is the maximum quantity of solute which can dissolve in a certain solution.

So Ksp expression = [Mg][F]^2

when Ksp = 8.4 x 10^-8 

[F] = 0.42

by substitution:

∴8.4 x 10^-8 = [Mg+] * (0.42)^2

∴[Mg+] = 4.8 x 10^-7 M

∴the solubility of MgF2 = 4.8 x 10^-7

The mass has escaped into a gas which you can not see so the law stays true.

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