Chemistry, 23.07.2019 13:30 23jazzy

What is the volume of a gas that exerts a pressure of 457 mm hg if it exerted a pressure of 2.50 atm when its volume was 25.0 ml?

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Answer from: riveg

$\boxed{{\text{103}}{\text{.94 mL}}}$ of gas exerts a pressure of 457 mm Hg.

Further Explanation:

Ideal gas:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept, and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is considered as the equation of state for any hypothetical gas. The expression for the ideal gas equation of gas is as follows:

${\text{PV}}={\text{nRT}}$ …… (1)

Here,

P is the pressure of the gas.

V is the volume of gas.

n denotes the number of moles of gas.

R is the gas constant.

T is the temperature of gas.

Boyle’s law:

It is an experimental gas law that describes the relationship between pressure and volume of the gas. According to Boyle's law, the volume of the gas is inversely proportional to the pressure of the system, provided that the temperature and the number of moles of gas remain constant.

If the temperature and number of moles of gas are constant then the equation (1) will become as follows:

${\text{PV}}={\text{constant}}$ …… (2)

Or it can also be expressed as follows:

${{\text{P}}_1}{{\text{V}}_1}={{\text{P}}_2}{{\text{V}}_2}$ …… (3)

Here,

${{\text{P}}_1}$ is the initial pressure.

${{\text{P}}_2}$ is the final pressure.

${{\text{V}}_1}$ is the initial volume.

${{\text{V}}_2}$ is the final volume.

Rearrange the equation (3) for ${{\text{P}}_2}$ , and we get,

${{\text{P}}_2}=\frac{{{{\text{P}}_1}{{\text{V}}_1}}}{{{{\text{V}}_2}}}$ …… (4)

The conversion factor to convert ${\text{atm}}$ into ${\text{mm Hg}}$ is as follows:

${\text{1 atm}}={\text{760 mm Hg}}$

The value of ${{\text{P}}_1}$ is 2.50 atm.

The value of ${{\text{V}}_1}$ is 25 mL.

The value of ${{\text{P}}_2}$ is 457 mm Hg.

Substitute these values in equation (4).

$\begin{aligned}{{\text{V}}_{\text{2}}}&=\frac{{\left( {{\text{2}}{\text{.50 atm}}}\right)\left({\frac{{760\;{\text{mmHg}}}}{{{\text{1}}\;{\text{atm}}}}}\right)\left({{\text{25 mL}}}\right)}}{{\left( {457\;{\text{mmHg}}}\right)}}\\&= {\text{103}}{\text{.938731 mL}}\\&\simeq {\text{103}}{\text{.94 mL}}\\\end{aligned}$

The final volume of a gas is 103.94 mL.

Learn more:

1. Determine the final pressure of the ideal gas:

2. Chemical bonds in NaCl:

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, pressure, volume, absolute temperature, equation of state, hypothetical, universal gas constant, moles of gas, initial, final.

Answer from: Quest

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.

Answer from: Quest

Most likely a is the answer - because you generate 38 atp's but also consume an atp. each atp gives approx. less than 4 kcal so probably a is the closest answer.