What volume of a 0.540 m naoh solution contains 15.5 g of naoh?

  The   volume   of  0.540m  NaOH   solution  that  contains  15.5 g  of   NaOH  is   calculated    as  follows

volume  =moles/molarity
find  moles  of  NaOH  =  mass/molar  mass
 =   15.5 g/  40  g/mol  =  0.3875  moles
volume  is therefore =  0.3875/  0.540  = 0.72  Liters
The  volume  is  in  liters  since  molarity  in  mole  per  liter

C. control over the business

The answer is c - the principal of original lateral continuity.