The ksp for silver(i) phosphate is 1.8 x 10 –18 . determine the silver ion concentration in a saturated solution of silver(i) phosphate

  The  silver  ion  concentration  in saturated  solution  of  silver (i) phosphate  is  calculated  as follows.

write  the  equation  for  dissociation of  silver (i)  phosphate
that  is  Ag3PO4 (s) =  3Ag^+(aq)   +  PO4 ^3-(aq)

let  the  concentration  of the  ion  be   represented  by  x
ksp  is  therefore=  (3x^3 )(x)  =  1.8  x10   ^-18

27 x^3 (x)  =  1.8  x10^-18
27x^4  =  1.8  x10^-18  divide both  side  27
X^4  =  6.67  x10  ^-20

find  the  fourth  root   x  =  1.6  x10 ^-5m

the  concentration  of  silver ion  is therefore = 3  x (1.6  x10^-5)  =  4.8  x10^-5m

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