Determine the mass of agcl formed when 0.847 grams of silver nitrate is reacted with 0.650 grams of nickel (ii) chloride

  The  mass  of  AgCl  formed  is  calculated  as  follows

write  the   equation  for  reaction

that  is  NiCl2   +2  Ag(No3)  >Ni(NO3)2   + 2  AgCl

find  the   moles  of   NiCl2   used
moles  = mass/molar  mass

=  0.650/129.69= 5.012   x10^-3  moles

by  use  of mole  ratio  between   NiCl2 to  AgCl  which  is    2:2  the moles  of  AgCl  is  also    5.012  x10^-3  moles

mass  =  moles  x  molar  mass
mass  of AgCl   is  therefore  = ( 5.012  x10^-3)  mol  x  143.37  g/mol=   0.719 grams

The number of medals awarded to the track team during the season.