Art a what is the kw of pure water at 50.0°c, if the ph is 6.630? what is the kw of pure water at 50.0°c, if the ph is 6.630? 1.00 × 10-14 2.13 × 10-14

Pure water is a neutral solution where the hydrogen ion concentration is equal the hydroxide ion concentration.
[H⁺] = [OH⁻]
kw is ionic constant for dissociation of water, therefore 
kw = [H⁺][OH⁻]
however since [H⁺] = [OH⁻]
kw = [H⁺]²
since pH is known, [H⁺] can be calculated
pH = -log[H⁺]
[H⁺] = antilog(-6.630)
[H⁺] = 2.34 x 10⁻⁷ M
kw = (2.34 x 10⁻⁷)²
kw = 5.5 x 10⁻¹⁴

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.