How many moles of zncl2 are produced when 0.033 moles of zn completely reacted?

The answer is 0.033 mol ZnCl2. From their coefficients in the balanced chemical equation for the reaction Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g), one mole of zinc is to produce one mole of zinc chloride and we use this mole ratio to compute for the number of moles of zinc chloride, that is also 0.033 mol:
     moles of ZnCl2 = 0.033mol Zn (1mol ZnCl2/1mol Zn) 
                               = 0.033 mol

             0.033 moles of Zn Metal

Solution:
The Balance chemical equation is as follow,
             Zn + 2 HCl > ZnCl2 + H2

According to this equation,
             1 mole of ZnCl2 is produced by reacting = 1 mole of Zn metal

So,
             0.033 moles of ZnCl2 will be produced by reacting = X moles of Zn metal

Solving and calculating X,
             X = (0.033 mol * 1 mol) / 1 mol
             X = 0.033 moles of Zn Metal

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