Ihave to take this quiz and i only have two questions left i do not want to fail! 1. for the following reaction, it is found that doubling the amount of a causes the reaction rate to double while doubling the amount of b causes the reaction rate to quadruple. what is the best rate law equation for this reaction? a + b -> 2c rate = k[a]2[b] rate = k[a][b] rate = k[a][b]2 rate = k[a]1/2[b] fill in the blank 2. determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. x + y --> products trial [x] [y] rate 1 0.20 m 0.15 m 2.4 × 10-2 m/min 2 0.20 m 0.30 m 4.8 × 10-2 m/min 3 0.40 m 0.30 m 19.2 × 10-2 m/min

1.

2.

x= 2 , y= 1 Total order= 2+1= 3

rate constant (k)=

Explanation:-

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

k= rate constant

x = order with respect to A

y = order with respect to A

On doubling the concentration of A, rate doubles thus order w.r.t A is 1.

On doubling the concentration of B, rate quadruples thus order w.r.t B is 2.

Thus

(2)  

    (1)

   (2)

Dividing 2 by 1

   (2)

   (3)

Dividing 3 by 2

rate law:

Total order = 2+1 = 3

using 1:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

the correct answer to this question is 2