Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . what is the theoretical yield of water formed from the reaction of of 5.23 g butane and of 27.1 g oxygen gas? round your answer to significant figures.

The theoretical yield of water is 1.18 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of butane = 5.23 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

Given mass of oxygen gas = 27.1 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of butane and oxygen gas follows:

By Stoichiometry of the reaction:

13 moles of oxygen gas reacts with 2 moles of butane

So, 0.085 moles of oxygen gas will react with = of butane

As, given amount of butane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

13 moles of oxygen gas produces 10 moles of water

So, 0.085 moles of oxygen gas will produce = of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 0.0654 moles

Putting values in equation 1, we get:

Hence, the theoretical yield of water is 1.18 grams

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