How many grams of kcl is produced if 32.4 grams of o2 is produced? 2kclo3(s) --> 2kcl(s) + 3o2(g) question 2 options: 0.54 grams kcl 6.87 grams kcl 25.7 grams kcl 50.3 grams kcl

Okay so, the molar mass (Mr) of O2 is 32g

moles = mass/Mr
moleS= 32.4/32= 1.0125mol
the Mr of KCl is 39.1+35.5= 74.6g

the ratio of moles of KCl to O2 is 2 : 3
therefore moles of KCl is (1.0125/3)×2= 0.675mols

mass =moles×Mr=0.675×74.6= 50.355g
rounds up to 50.3g therefore last answer is correct

It is called a neutralization reaction