Find the h3o+ concentration of a 0.210 m hypochlorous acid solution (whose acid dissociation constant is ka=2.9×10−8).

Given that:
Ka = 2.9 x 10⁻⁸      and [HClO] = 0.210 M
Ka = 
                    HClO + H₂O → H₃O⁺ + ClO⁻
Initial           0.210                   0           0
Change         -x                      +x          +x
Equilibrium  (0.210-x)             x             x
so:
2.9 x 10⁻⁸ = 
solving x:
x = 7.8 x 10⁻⁵
so [H₃O⁺] = 7.8 x 10⁻⁵ M

8.7 degrees celsius and 15.6 degrees fahrenheit

No is the answer to the question