If i have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205 k)

Hello!

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

The temperature is approximately 205 Kelvin

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I Hope this helps, greetings ... Dexteright02! =)

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