Carbon disulfide is an important industrial solvent. it is prepared by the reaction of coke with sulfur dioxide. 5c(s)+2so2(g)-> cs2(l)+ 4co(g)

I added a screenshot with the complete question.

Part (a):
The balanced equation given is:
5C(s) + 2SO₂(g) ........> CS₂(l) + 4CO(g)From this equation, we can note that 5 moles of C are required to form 1 mole of CS₂. Therefore, to know the number of moles formed from 2.7 moles of C, we will use cross multiplication as follows:
5 moles of C ..............> 1 mole of CS₂
2.7 moles of C ............> ?? moles of CS₂
number of moles of CS₂ = (2.7*1) / 5 = 0.54 moles

Part (b):
The balanced equation given is:
5C(s) + 2SO₂(g) ........> CS₂(l) + 4CO(g)From this equation, we can note that 5 moles of C are required to react with 2 mole of SO₂. Therefore, to know the number of moles of carbon needed to react with 5.44 moles of SO₂, we will use cross multiplication as follows:
5 moles of C ..............> 2 mole of SO₂
?? moles of C ............> 5.44 moles of SO₂
number of moles of SO₂ = (5.44*5) / 2 = 13.6 moles

Part (c):
The balanced equation given is:
5C(s) + 2SO₂(g) ........> CS₂(l) + 4CO(g)From this equation, we can note that 4 moles of CO are formed when 1 mole of CS₂ is formed. Therefore, to know the number of CO moles formed from 0.246 moles of CS₂, we will use cross multiplication as follows:
4 moles of CO ..............> 1 mole of CS₂
?? moles of CO ............> 0.246 moles of CS₂
number of moles of CS₂ = (0.246*4) / 1 = 0.984 moles

Part (d):
The balanced equation given is:
5C(s) + 2SO₂(g) ........> CS₂(l) + 4CO(g)From this equation, we can note that 2 moles of SO₂ are required to form 1 mole of CS₂ is formed. Therefore, to know the number of SO₂ moles required to form 118 moles of CS₂, we will use cross multiplication as follows:
2 moles of SO₂ ..............> 1 mole of CS₂
?? moles of SO₂ ............> 118 moles of CS₂
number of moles of SO₂ = (118*2) / 1 = 236 moles

Hope this helps :)

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

It will fall off and tip over.