How many grams of calcium nitrate would react with 4.55 moles of chromium (iii) sulfate to produce calcium sulfate and chromium (iii) nitrate? a.) 6.86x10^2 g b.) 3.43x10^2 g c.) 6.04x10^-2 g d.) 3.09x10^3 g

The equation of the reaction is;
3Ca(NO3)2 + Cr2(SO4)3 = 3Ca(SO4) + 2 Cr(NO3)3
4.55 moles of chromium (iii) sulfate reacts with calcium nitrate
The mole ratio of Chromium (iii) sulfate to calcium nitrate is 1: 3
Therefore; the moles of calcium nitrate will be given by 
  = (4.55/ 1)×3
 = 13.65 moles
Hence; 13.65 moles of calcium nitrate would react with 4.55 moles of Chromium (iii) sulfate.

Butterfly wingspan is 7.7

The correct answer should be "electrons orbit the nucleus in circular motions exactly as shown on the classic bohr model."