As a 15.1-gram sample of a metal absorbs 48.75 j of heat, its temperature increases 25.0k. what is the specific heat capacity of the metal? a) 0.129 j/gk b) 1.95 j/gk c) 3.23 j/gk d) 7.74 j/gk

As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0K. is the specific heat capacity of the metal

Option A

Explanation:

Specific heat term explains the amount of heat needs to be added with unit mass in order to increase the temperature by a degree Celsius. Its formula is given by,

Where,

Plugging in the values  

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explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g