Determine the percent composition by mass of the element carbon in the acetamide compound

The formula of acetamide is C2H5NO
It contains 2 atoms of carbon 
The atomic mass of carbon is 12; therefore 2 atoms of carbon contains 24 g
The mass of 1 mole of acetamide is 59.07 g/mol
Therefore; the percentage of carbon in asetamide will be'
 =24/59.07 ×100
 = 40.63 %
 

Polymerization reaction

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