Name the following compound: ch3 – ch2 – ch2 – o – ch2 – ch2 – ch2 – ch3 1: butyl propyl ether. 2: propyl butyl ether. 3: 3-butyl propyl ether. 4: 4-propyl butyl ether.

option 1: butyl propyl ether

Explanation:

1) Idenfify the functional group: R - O - R' => ether

2) Name the alkyl groups

a) CH3 – CH2 – CH2 – : 3 carbons => propyl

b) – CH2 – CH2 – CH2 – CH3: 4 carbons => butyl

3) rule: name the subtituents in alphabetcial order => first butyl, second propyl

4) Result: buty propyl ether.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.