A10.0-l rigid container holds 3.00 mol h2 gas at a pressure of 4.50 atm. what is the temperature of the gas?

We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.

Answer. A. 183

B. 142

C. 0.03

D.11.3

E.24.5

Explanation:

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Sorry i dont understand the question can you rephase it?