Choose all that apply. gas pressure within a fixed container will increase when a) gas is cooled b) gas is heated c) gas volume changes d) mass of gas is increased

Gas pressure within a fixed container will increase when gas is heated and also when mass of gas is increased.

Options B and D

Explanation:

In a closed container, the temperature is proportional to pressure according to the pressure law. When the gas presents in a container, it means that the size of the container remains constant unless/until it is changed by increasing its size or decreasing it.

When the container gets heated, gas particles gains more kinetic energy, moves faster and hits the inner walls of the container. The amount of gas particles also seems to be more.

And so, it hits the container's wall more frequently and with more speed and force. Hence, these make the gas pressure in the container to increase. According to the Boyle’s law,

Where, p – pressure, V – volume, n – no. of moles, R – gas constant, T – temperature.

This also tells the reason how the gas pressure increases when the amount of gas and temperature get increased.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

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