How many grams of nitroglycerin are needed to produce 25.0 grams of co2

Nitroglycerin  decomposes    according  to   the   following  equation

4 C3H5N309  --->  12 CO2 +  10 H20  +  6 N2 +O2
The  moles  of  CO2 =  25 /44(molar  mass  of  CO2)=  0.568  moles

the  mole  ratio  of  C3H5N3O9  to  CO2  IS  4:12   from  equation  above
therefore  the  moles  of  C3H5N3O9=( 0.568 x 4)/12= 0.189  moles
mass  of C3H5N3O9=moles  x  molar  mass  of  C3N5N3O9

That  is    0.189 mol x  227  g/mol=  42.903  grams

Well to my expert knowledge and my exquisite calculations i think the the negative ion # 412 is the key to sucess