Acertain gas is present in a 12.0 l cylinder at 4.0 atm pressure. if the pressure is increased to 8.0 atm the volume of the gas decreases to 6.0 l . find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys boyle’s law by entering the numerical values for ki and kf in the space provided.

There are 3 parts in this question:
1) To find the initial Boyle's constant
2) To find the final Boyle's constant
3) To verify whether gas is obeying Boyle's law or not

Given data:
The initial volume of the cylinder(in litres) =  = 12.0 L
The initial pressure(in atmospheric pressure) =  = 4.0 atm

The final pressure(in atmospheric pressure) = = 8.0 atm
The final volume of the cylinder(in litres) =  = 6.0 L

First you need to know what Boyle's law is:
Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

The Mathematical form of Boyle's law is:


Where,
P = Pressure
V = Volume of the gas
k = Boyle's constant

Now let's solve aforementioned parts one by one:
1. 
The initial volume of the cylinder(in litres) =  = 12.0 L
The initial pressure(in atmospheric pressure) =  = 4.0 atm
The Boyle's constant = = ?

According to the Boyle's law,



=>  =  
Plug-in the values in the above equation, you would get:
= 4.0 * 12.0 = 48

Ans-1) = 48

2.
The final pressure(in atmospheric pressure) = = 8.0 atm
The final volume of the cylinder(in litres) =  = 6.0 L
The Boyle's constant = = ?

According to the Boyle's law,



=>  =  
Plug-in the values in the above equation, you would get:
= 8.0 * 6.0 = 48

Ans-2) = 48

3.
In order to verify Boyle's law, the initial Boyle's constant should be EQUAL to the final Boyle's constant, meaning:

= 

Since,
= 48
= 48

Therefore,
48=48.

Ans-3) Hence proved: The gas IS obeying the Boyle's law.

-i

The air is going to come out because of the low pressure.